151.--THE JOINER'S PROBLEM.

From Amusements in Mathematics by Henry Ernest Dudeney.

[Illustration]

Nothing could be easier than the solution of this puzzle--when you know how to do it. And yet it is apt to perplex the novice a good deal if he wants to do it in the fewest possible pieces--three. All you have to do is to find the point A, midway between B and C, and then cut from A to D and from A to E. The three pieces then form a square in the manner shown. Of course, the proportions of the original figure must be correct; thus the triangle BEF is just a quarter of the square BCDF. Draw lines from B to D and from C to F and this will be clear.

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151.--THE JOINER'S PROBLEM.: Amusements in Mathematics by Henry Ernest Dudeney | amphi